Calculating radius of the core with just densities

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SUMMARY

The discussion focuses on calculating the radius of the Earth's core using given densities: Earth's average density (Pe = 5,515 kg/m³), core density (Pc = 11,000 kg/m³), and mantle-crust density (Pm = 4,450 kg/m³). The gravitational equation g = (GM)/r² is mentioned but deemed inappropriate for this density-based problem. The correct approach involves considering the Earth as a two-layered sphere, where the inner core has a radius (rc) and the outer shell extends to the Earth's radius (Re = 6377 km). Participants emphasize the need to calculate average density rather than gravitational forces.

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Homework Statement


Calculate the radius of the Earth's core using the following data:

Pe = 5,515 kg/m^3 (earth's average density)
Pc = 11,000 kg/m^3 (core's density)
Pm = 4,450 kg/m^3 (mantle-crust density)

Re = 6377km (radius of the earth)


Homework Equations


im guessing we should be using the gravitational equation

g = (GM)/r^2 for different shells (might be wrong)

g= gravitational acceleration
G= Gravitational constant
M = mass of sphere with radius of "r"
r= radius


The Attempt at a Solution



i tried the above equation but got no where with this. i need help!
 
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You're dealing with densities, not forces. If the Earth consists of an inner sphere of one density and an outer shell of another density, how would you calculate the average density? Suppose that the inner sphere has radius rc and that the outer shell extends to radius Re (radius of the Earth).
 

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