Calculating rates of two points moving along a circle

  • MHB
  • Thread starter DaalChawal
  • Start date
  • #1
DaalChawal
96
0
1638445882433.png



Question 3
 

Answers and Replies

  • #2
skeeter
1,104
1
Let $v_1 > v_2$ be the respective speeds (rates) in feet per second of the two particles.

Moving in opposite directions, their rate of closure is $(v_1+v_2)$

Moving in the same direction, their rate of opening is $(v_1-v_2)$

Set up a system of two equations and solve for both speeds.
 
Last edited by a moderator:
  • #3
DaalChawal
96
0
You have added them like they are moving on straight line...In circle velocity changes as direction is changing.
 
  • #4
skeeter
1,104
1
You have added them like they are moving on straight line...In circle velocity changes as direction is changing.

If the two particles move in opposite directions, the sum of their respective distances traveled in 5 seconds will be one full circumference length when they meet again.

If the two particles move in the same direction, the faster particle will move ahead of the slower particle, hence the difference between their respective distances traveled in 25 seconds will be one full circumference length when they meet again.

Using this method, I get $v_1 = 18 \, ft/sec$ and $v_2 = 12 \, ft/sec$. You can check the results yourself.
 
  • #5
HOI
923
2
This problem has nothing to do "velocity". The problem asks for their speeds, not their velocities.
 

Suggested for: Calculating rates of two points moving along a circle

Replies
1
Views
517
Replies
13
Views
569
Replies
7
Views
307
  • Last Post
Replies
19
Views
304
  • Last Post
Replies
3
Views
917
  • Last Post
Replies
3
Views
280
Replies
1
Views
369
Replies
13
Views
686
Replies
3
Views
419
Replies
2
Views
718
Top