Calculating Reaction Forces in ANSYS: Step-by-Step Guide"

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Discussion Overview

The discussion revolves around calculating reaction forces in an ANSYS model, specifically focusing on discrepancies between hand calculations and ANSYS results. Participants explore the implications of applied moments, support conditions, and geometric considerations in the context of structural analysis.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • Some participants inquire about the method to derive the reaction forces of +121 N and -121 N from hand calculations, referencing a specific model.
  • Others propose that the model represents a block subjected to a z-axis torque of 100 Nm, suggesting that the restraining forces should be approximately 91 N based on their calculations.
  • One participant notes that the moment is about the y-axis and reiterates the calculation of 91 N, indicating a consistent result across their reasoning.
  • There is a discussion about the discrepancy between the hand calculations (91 N) and the ANSYS results (121 N), with some participants questioning the cause of this difference.
  • One participant suggests that the discrepancy may arise from an offset in the application point of the moment relative to the shaft's centerline, which is not clearly defined in the model.
  • Another participant questions whether the forces at the shaft endpoints should be considered normal to the torque axis, expressing confusion over how this affects the calculated forces.
  • One participant simplifies the model to test if dimensions influence the results and conducts a parametric study, noting that as the length R decreases, the relative difference between hand calculations and ANSYS results also decreases.
  • A participant unfamiliar with ANSYS asks if varying other parameters could provide insights into the discrepancies and mentions the smoothness of the graph as a concern.
  • Another participant clarifies that their hand calculations initially considered only forces at the ends of the shaft, but acknowledges that a fully fixed condition would also involve moments at each end.
  • A later post introduces a free body diagram (FBD) of the system and poses a question about solving the statically indeterminate system, suggesting a potential approach of splitting it into simpler beam cases.

Areas of Agreement / Disagreement

Participants express differing views on the calculation of reaction forces, with some supporting the hand calculation result of 91 N and others aligning with the ANSYS output of 121 N. The discussion remains unresolved regarding the exact cause of the discrepancy and the appropriate method for analysis.

Contextual Notes

Participants note limitations in the clarity of dimensions in the model, the nature of support conditions (pinned vs. fully fixed), and the implications of moment application points, which may affect the calculations. There are also unresolved mathematical steps related to the statically indeterminate nature of the system.

Laurry
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Hey,

I have a simple ANSYS model shown in link:
https://dl.dropboxusercontent.com/u/104865119/hand_calc.PNG .

Ansys reaction force in z axis is +121 N and -121 N. Can someone clarify how do you
get to this result using hand calculations?
 
Last edited by a moderator:
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Laurry said:
Hey,

I have a simple ANSYS model shown in link:
https://dl.dropboxusercontent.com/u/104865119/hand_calc.PNG .

Ansys reaction force in z axis is +121 N and -121 N. Can someone clarify how do you
get to this result using hand calculations?
I need some description of what the diagram represents. It looks like a block somehow subjected to a z-axis torque of 100Nm, while restrained at two points 1.1m apart. But in that case the restraining forces would obviously be 100/1.1N, or about 91N.
 
Last edited by a moderator:
Using the global coordinate system found in the picture the moment is about the y axis, My = 100Nm.

https://dl.dropboxusercontent.com/u/104865119/hand_calc_2.PNG
 
Last edited by a moderator:
Laurry said:
Using the global coordinate system found in the picture the moment is about the y axis, My = 100Nm.

https://dl.dropboxusercontent.com/u/104865119/hand_calc_2.PNG
Ok, but same result. 91N, as you say.
 
Last edited by a moderator:
Does anyone have an idea what could cause this discrepancy (121 vs 91 N) between hand calc and Ansys?
 
The problem appears to me to be an apparent offset of the point at which you are applying the moment from the centerline of the shaft (for which you are showing no dimension). Since there is no x restraint at moment application point then the moment due to that offset must be carried by the shaft as opposed to being a x direction vector force on the shaft restraints.
 
JBA said:
The problem appears to me to be an apparent offset of the point at which you are applying the moment from the centerline of the shaft (for which you are showing no dimension). Since there is no x restraint at moment application point then the moment due to that offset must be carried by the shaft as opposed to being a x direction vector force on the shaft restraints.
Are you suggesting we should take the forces applied at the shaft end points as being normal to the line joining them to the torque axis?
That does not seem to help. It makes the forces less, not more.
 
I made the simple model even simpler using even numbers in order to find out if dimensions can somehow explain the difference.

https://dl.dropboxusercontent.com/u/104865119/ansys2.PNG

Did also a parametric study in Ansys and found out that as the length R decreases, the relative difference between results decreases.
 
Last edited by a moderator:
Laurry said:
I made the simple model even simpler using even numbers in order to find out if dimensions can somehow explain the difference.

https://dl.dropboxusercontent.com/u/104865119/ansys2.PNG

Did also a parametric study in Ansys and found out that as the length R decreases, the relative difference between results decreases.
I have no idea what ANSYS is. Can you vary other parameters to get a clue as to what affects it? Can you get more precision out of it - the graph is not very smooth.
 
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  • #10
Pinned v fully fixed .
 
  • #11
Thanks for the answer. In hand calculations I assumed only forces in the ends of the shaft but for it to be fully fixed there should also be a moment in each end.
By allowing the computer model's surfaces to rotate around the vertical axis, representing a pinned support, I got the same result.
 
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  • #12
A continuation to this problem. I drew the correct FBD of the system, shown in the link:

http://imgur.com/a/AkTci

How is this statically indeterminate system solved? My first guess was to split it into beams which are table cases.
 

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