Calculating Resistance(not at RT) using the Resistivity Formula

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The discussion centers on calculating resistance using the resistivity formula, particularly under non-standard temperature conditions. The user notes that their experimental results were consistently higher due to a room temperature of 28°C, leading to a systematic error. They seek clarification on the formula R=(L/A)ρ=(L/A)ρ0(α(T - T0)+1), specifically regarding the meanings of ρ0, α, and T0, and how to apply it to the "Constantan" alloy. Additionally, they request examples that incorporate temperature effects in resistance calculations. Resources for Constantan properties are shared to aid in their research.
Jozers
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For my coursework "Resistance in a Wire" I used the R=ρL/A formula to predict what resistance I should get. Yet, as it was a hot day:mad: when i did the experiment the Room Temperature was not ambient but 28°C. Therefore my there was a small systematic error with my results (they were consistantly higher than predicted). I wish to show that this error was due to the temperature and would like to use the formula

R=(L/A)ρ=(L/A)ρ0(α(T - T0)+1)

I'm think that ρ0 is the residual resistance, α is the thermal resistance and T0 is room temperature. Could someone just clarify this? And where could i find out these properties for "Constantan" Alloy? As iv'e been unsuccessful of find these on the internet.

I would also be useful if someone knows of and example (which include the Temp. part) explaining how to use this formula, it should be easy to figure out but any help would be great. :smile:

Thanks
Jozers
 
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Thank you Astronuc.
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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