Calculating Rocket's Acceleration & Velocity

In summary, a rocket with constant acceleration blasts off straight upward and reaches a height of 80m after 3 seconds. Using the equations v=v_0+at and x=x_0+v_0t+\frac{1}{2}at^2, it is possible to find the magnitude and direction of the rocket's acceleration, as well as its velocity at the given time. By finding the average velocity and doubling it, the final velocity can be determined and used to find the acceleration.
  • #1

Homework Statement


A rocket blasts off with constant acceleration straight upward. After 3 seconds the rocket is at a height of 80m. (a) what are the magnitude and direction of the rocket's acceleration? (b) what is its velocity at the time

Homework Equations



[itex] v=v_0+at [/itex]
[itex] v^2=V_0^2+2a\Delta x [/itex]
[itex] a=v^2-v_0/(2*x) [/itex]
[itex] x=x_0+v_0t+\frac{1}{2}at^2[/itex]

The Attempt at a Solution


None, because I was unsure how to proceed as using these equations would result in one unknown (either v or a)
 
Last edited:
Physics news on Phys.org
  • #2


You are missing one equation, the that gives the position as a function of time.
 
  • #3


ok, will add that
 
  • #4


The 4th equation looks promising!
 
  • #5


Yeah i realize that now, plugged in and got acceleration-now i need to just plug acceleration into get velocity! thanks
 
  • #6


frostcloak said:
Yeah i realize that now, plugged in and got acceleration-now i need to just plug acceleration into get velocity! thanks

With constant acceleration from rest, the average velocity is one half of the final velocity.

This rocket covered 80m in 3 seconds, so average velocity is easy to find. Double that and you have the final velocity.

Once you have that final velocity you can easily get acceleration since you know by how much the velocity changed in 3 seconds.
 

Suggested for: Calculating Rocket's Acceleration & Velocity

Back
Top