- #1
Pinon1977
- 126
- 4
I need some outside opinions on determining the available torque on a prime mover.
I have a mechanical advantage prime mover (or driver) that creates rotation of its overall mass via a series of offset mass movements within the driver. It's primary power source is gravity; however, movement is also done pnumatically via a Fibonacci engine which supplies the aforementioned air requirements.
Basically what I have is a giant flywheel turns at about 18 RPMs and has a moment of inertia of approximately 8700 kg per meter squared. I'm trying to determine, based upon the aforementioned information, what the available torque would be at the axle of the driver. My first thought would be to multiply the moment of inertia body angular velocity and that would give you a Value in Newton the meters. Or, otherwise, 8700 kilograms per meter squared times 1.83 radians per second equals roughly 15921 Newton meters.
I have a mechanical advantage prime mover (or driver) that creates rotation of its overall mass via a series of offset mass movements within the driver. It's primary power source is gravity; however, movement is also done pnumatically via a Fibonacci engine which supplies the aforementioned air requirements.
Basically what I have is a giant flywheel turns at about 18 RPMs and has a moment of inertia of approximately 8700 kg per meter squared. I'm trying to determine, based upon the aforementioned information, what the available torque would be at the axle of the driver. My first thought would be to multiply the moment of inertia body angular velocity and that would give you a Value in Newton the meters. Or, otherwise, 8700 kilograms per meter squared times 1.83 radians per second equals roughly 15921 Newton meters.