Calculating the torque required to rotate a ski on snow

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Discussion Overview

The discussion revolves around calculating the torque required to rotate the front skis of a toboggan during a competition project. Participants explore factors influencing torque, including friction and ski dimensions, as well as the relevance of moment of inertia.

Discussion Character

  • Technical explanation, Exploratory, Debate/contested

Main Points Raised

  • One participant mentions having determined the normal force and frictional force on each ski but feels additional information is needed to calculate the torque required to overcome friction.
  • Another participant suggests that a larger ski may require more torque to overcome friction, prompting a question about how to factor in surface area.
  • A participant raises the question of whether moment of inertia is relevant to the torque calculations.
  • Clarification is sought regarding the nature of the competition, with one participant explaining the structure of the toboggan and the configuration of the skis.
  • Another participant inquires about the location of the pivot center for the skis, asking whether it is leading or trailing.
  • The original poster specifies that the pivot axis is centered on each ski, which are 24 inches in length.

Areas of Agreement / Disagreement

Participants are exploring various aspects of the torque calculation, but there is no consensus on the specific factors that should be considered or how they should be applied.

Contextual Notes

The discussion includes assumptions about the relationship between ski size and required torque, as well as the need for clarity on the pivot axis, which may influence the calculations.

Blurp
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Hello friends,

I'm currently working on an engineering competition project known as the Great Northern Concrete Toboggan Race, and I'm stuck on some preliminary calculations. I'm trying to calculate the amount of torque that will be required to rotate the front skis in order to turn the toboggan. I have determined a normal force on each ski, and therefore a frictional force, but I believe I am missing information required to calculate the true torque needed to overcome friction. Common sense tells me a larger ski will require more torque to overcome friction, so how do I factor in surface area? Is moment of inertia also relevant?

Any insight would be much appreciated, thank you.
 
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What do you mean by Concrete Toboggan Race ?
 
Nidum said:
What do you mean by Concrete Toboggan Race ?

It's a competition for engineering students. It's essentially a steel roll cage with a concrete running surface. In my case, there's two fixed skis in the back and two skis in the front that will be able to pivot. I'm trying to figure out how much force it will take to achieve that pivoting
 
Where's the "pivot center" located? Leading? Trailing?
 
The pivot axis is centered on each ski, which are 24 inches in length
 

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