This should be an easy one, but my answer does not seem right to me. I was hoping someone to verify for me. If you have a spool filled with rope that weighs 2,000 LBS on a frictionless axle. Determine the tangential force required to move the spool by pulling the rope. Given: Weight of spool = 907.18 KG Diameter of spool = 1.22 Meters Angular Acceleration = 2.093 RADs per Second Length of spool = .74 Meters T = Torque A = Angular Acceleration R = Radius of spool in meters Explanation of calculations: I calculated the moment of inertia for the full spool and used it to derive the torque (knowing the angular acceleration) and then derived force out of the torque equation. Calculations: I = 1/2*M*(L squared) I = .5*907.18*.547 I = 248.11 KG*(Meters squared) Moment of inertia in Kg*Meters - squared If I = T/A then 248.11*2.093 = T T = 519.29 Newtons*Meters If T = F*R then 519.29 / .61 = F F = 851.29 Newtons As far as my tension in rope I assume it to be equal to F at 851.29 Newtons Is this correct? The value seems high to me. Please advise.