Calculating Scattered Light Intensity at Different Wavelengths

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
1 reply · 2K views
senobim
Messages
34
Reaction score
1

Homework Statement


Light is scattered in cuvette by Reyleigh scattering, and is measured by monochromator.
Light intesity is given by I(ν)=I0ν1/2 relationship

What is scattered light intensity at λ = 400nm if at λ = 800nm is I800?

Homework Equations



Scattered light intensity is proportional to I = 1/λ4

and ν = c/λ --> I(λ) = I0(c/λ)1/2

The Attempt at a Solution


That's about it I can think of about this problem, any hints would be appreciated! ;]
 
Physics news on Phys.org
Your scattered light intensity is the product of the initial light intensity (which you transformed already) and the fraction that gets scattered (where you have the relation).

It is a bit unclear if intensity is meant "per interval of ν" or "per interval of λ". If the intensity formula and the answer use different conventions you would have to transform that.