Calculating Speed for Banked Racing Track

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SUMMARY

The discussion focuses on calculating the speed for a car on a banked circular racing track, considering both frictionless conditions and wet track scenarios. For a frictionless track, the speed is determined using the formula v^2/R, where R is the radius of the track. When friction is introduced with a coefficient of u=0.15, the minimum and maximum speeds are calculated by incorporating the frictional force into the equations of motion, specifically a_f=u*g*cos(theta).

PREREQUISITES
  • Centripetal acceleration concepts
  • Understanding of banked curves in physics
  • Knowledge of friction coefficients and their effects
  • Basic trigonometry involving angles and forces
NEXT STEPS
  • Study the derivation of centripetal acceleration formulas
  • Learn about the effects of friction on motion in circular paths
  • Explore the physics of banked curves in racing dynamics
  • Investigate real-world applications of these principles in motorsport engineering
USEFUL FOR

Physics students, automotive engineers, and anyone interested in the dynamics of racing vehicles on banked tracks will benefit from this discussion.

superdave
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Homework Statement


Car is driven on a banked circular racing track. Radius R, angle theta.

a) For what speed is the track designed (if there were no friction the car would not slide)
b) If the track is wet, u=0.15, what are the minimum and maximum speeds car must be driven so it stays on the track.


Homework Equations


a=v^2/R (centripetal)
a=sin (theta) * g
a_f=u*g*cos(theta) (for part b, friction)

The Attempt at a Solution



Okay, here's what I don't understand.

Centripetal force pulls the car towards the center. And gravity pulls the car down, again towards the center. So though I know they oppose each other, I can't figure out why they would oppose each other since it seems they don't.
 
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In my experience these banked road questions are best worked with from the point of view of the car, where you have a centrifugal force rather than a centripetal one. Further to make sense of it, you have to find the components of both forces that are normal to the road and parallel to it. The total normal force determines the friction force. Then you work with the 3 forces parallel to the road to find your answers.
 

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