Calculating Speed of Ball After Racket Strike

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SUMMARY

The discussion centers on calculating the speed of a 116 g ball after being struck by a racket while traveling at 34 m/s. The force applied to the ball, directed to the right over a contact time of 21 ms, is represented graphically. The impulse-momentum theorem is utilized, where impulse (I) is defined as the product of force (F) and time (T), leading to the equation I = F x T. The area under the force-time graph provides the impulse, which, when divided by the mass of the ball, yields the change in velocity.

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  • Understanding of impulse-momentum theorem
  • Familiarity with force-time graphs
  • Basic knowledge of mass and velocity concepts
  • Ability to calculate area under a curve
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  • Calculate impulse using the area under the force-time graph
  • Apply the impulse-momentum theorem to determine final velocity
  • Explore examples of impulse calculations in physics
  • Review concepts of momentum and its conservation
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Students studying physics, particularly those focusing on mechanics and impulse, as well as educators looking for practical examples of force and motion interactions.

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Homework Statement


A 116 g ball is traveling to the left with a speed of 34 m/s when it is struck by a racket. The force on the ball, directed to the right and applied over 21 ms of contact time, is shown in the graph. What is the speed of the ball immediately after it leaves the racket?

this graph comes with it
http://www.webassign.net/grr/p7-16.gif


Homework Equations


I know it has something to do with impluse so I = F x T


The Attempt at a Solution


i have no idea!
 
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try F\Delta t = m\Delta v

area under the graph = impulse, divide by mass = velocity
 
Yes, that formula is needed since I=\Delta \rho where \Delta \rho=change in momentum.
All you need to do to find the impulse is calculate the area under the graph.
 

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