Calculating Speed of Bowling Ball Down Incline

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SUMMARY

The discussion focuses on calculating the translational speed of a bowling ball with a mass of 5.45 kg and a radius of 0.191 m as it rolls down a 22.3 m incline from a height of 1.8 m. The relevant energy equation used is E = mgh + 1/2 mv² + 1/2 Lω². Participants emphasize the need for additional equations to define the moment of inertia (I) and angular velocity (ω), and stress the importance of distinguishing between initial and final positions in energy calculations.

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Homework Statement


a bowling ball with a mass of 5.45kg and a radius of .191m starts from the rest at a height of 1.8m and rolls down a 22.3m slope. what is the translational speed of the ball when it leaves the incline.


Homework Equations



E=mgh +1/2mv^2+1/2Lw^2

The Attempt at a Solution


E=5.45kg*9.81m/s*1.8m+ 1/2 %.45kg* v^2+1/2 Lw^2
?is this even right?
 
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Hi physicsgurl12! :smile:

physicsgurl12 said:

Homework Equations



E=mgh +1/2mv^2+1/2Lw^2

The Attempt at a Solution


E=5.45kg*9.81m/s*1.8m+ 1/2 %.45kg* v^2+1/2 Lw^2
?is this even right?

You need more relevant equations.
That is, you need one for L (although the symbol is usually I), and you need one for w (for which the symbol is usually ω).
Can you get those?

Furthermore you need to make a distinction between the initial position, where v and w are zero, and the final position, where h is zero.

The energy E in both the initial position and the final position must be the same.
 

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