Calculating Speed of Halley's Comet at Aphelion/Perihelion

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SUMMARY

The speed of Halley's Comet at aphelion and perihelion can be calculated using the formula v² = (4Π²a³) / (P²) * ((2/r) - (1/a)), where 'a' is the semimajor axis (16.8 A.U.), 'P' is the sidereal period (75 years), and 'r' is the distance from the Sun. At perihelion, 'r' is calculated as a - c (16 A.U.), while at aphelion, 'r' is a + c. It is crucial to convert units from astronomical units and years to meters and seconds for practical results. Additionally, conservation of angular momentum can be applied, leading to the relationship v_perihelion r_perihelion = v_aphelion r_aphelion.

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  • Understanding of Kepler's laws of planetary motion
  • Familiarity with the concepts of perihelion and aphelion
  • Knowledge of unit conversion from astronomical units to meters and years to seconds
  • Basic principles of angular momentum in physics
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  • Research the application of Kepler's laws in celestial mechanics
  • Learn about unit conversion techniques for astronomical calculations
  • Explore the concept of angular momentum and its conservation in orbital mechanics
  • Investigate the historical observations and calculations of Halley's Comet's orbit
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Astronomers, physics students, and anyone interested in celestial mechanics and the dynamics of cometary orbits will benefit from this discussion.

swelzba9
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I am trying to figure out the speed of Halley's Comet in km/sec. at aphelion and perihelion... my answers just don't seem to be practical.. please help thanks...


I am using

v² = (4Π²a³) / (P²) * ((2/r) - (1/a))

where a = mean distance from the sun (semimajor axis of the ellipse)
P= sidereal period (75 years)
r = distance of the object from the Sun at a given instant

a=16.8 A.U. c=16 A.U.

"r" at perihelion = a-c "r" at aphelion = a + c
 
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Well, what are your answers?

I see that you have quoted units in terms of years and astronomical units. Did you convert these units to seconds and meters, respectively?

As a reference point for your answers, know that the Earth moves through space in its orbit about the sun around 30 km/s, which is quite fast relative to what we are accustomed to in our daily experiences living on earth.
 
Maybe this will add another equation for a simultaneous solution? Conservation of angular momentum. Perihelion and aphelion are the two points where the radius vector from the sun to the comet is perpendicular to the tangential velocity of the comet, so the sin theta drops out of the expression for angular momentum and it's just mvr. Then mass cancels out, so v_perihelion r_perihelion = v_aphelion r_aphelion.
 

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