Calculating Speed to Catch a Ball Thrown from a Building

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SUMMARY

A ball is thrown upward from a height of 25.6 meters with an initial speed of 12 m/s. To determine the average speed required for a person running from a distance of 29.4 meters to catch the ball at the bottom of the building, one must calculate the time it takes for the ball to reach the ground using kinematic equations. The equations of motion will provide the necessary time, which can then be used to compute the required speed of the runner to cover the 29.4 meters in that same time frame.

PREREQUISITES
  • Kinematic equations of motion
  • Understanding of initial velocity and acceleration
  • Basic principles of projectile motion
  • Concept of average speed calculation
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  • Study the kinematic equations for uniformly accelerated motion
  • Learn how to calculate the time of flight for a projectile
  • Explore the concept of relative motion in physics
  • Practice problems involving projectile motion and average speed
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Students struggling with physics concepts, educators teaching kinematics, and anyone interested in understanding projectile motion and speed calculations.

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im practically lost in physics and need some help. it would be greatly appreciated.

A ball is thrown upward from the top of a 25.6 m tall building. The ball's initial speed is 12 m/s. At the same instant, a person is running on the ground at a distance of 29.4 m from the building. What must be the average speed of the person if he is to catch the ball at the bottom of the building?

i am really lost in physics , and need some help. it would be greatly appreciated. thankyou

A ball is thrown upward from the top of a 25.6 m tall building. The ball's initial speed is 12 m/s. At the same instant, a person is running on the ground at a distance of 29.4 m from the building. What must be the average speed of the person if he is to catch the ball at the bottom of the building?
 
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What are the equations that relate position, velocity and acceleration of an object? Use those equations to figure out how the ball moves with time as it goes up, stops at the top of its arc, and then accelerates down. These equations will let you figure out what time the ball will reach the bottom of the building. Then given the distance of the runner initially, you can figure out the speed needed to get the runner there at the same time. Too bad they didn't tell you how tall the runner is -- I guess you have to assume that they make a shoestring catch (catch the ball just as it reaches the ground).
 
The elapsed time for the ball to reach the ground will be the same time for the catcher to cover the 29.4 meters (and then splat against the wall!).
 

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