Calculating Spring Compression from Toy Car Collision

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SUMMARY

The discussion focuses on calculating the compression of a spring when a toy car with a mass of 0.079 kg collides with it at a velocity of 1.10 m/s. The spring has a constant of 69 N/m. The relevant equation for Elastic Potential Energy (EPE) is identified as EPE = kx²/2, where x is the compression distance. The user seeks clarification on how to apply the mass and velocity in this context to determine the spring's compression.

PREREQUISITES
  • Understanding of Elastic Potential Energy (EPE)
  • Knowledge of Hooke's Law and spring constants
  • Basic principles of conservation of energy
  • Familiarity with unit conversions, particularly Joules
NEXT STEPS
  • Calculate the initial kinetic energy of the toy car using KE = 0.5 * m * v²
  • Apply the conservation of energy principle to equate kinetic energy to elastic potential energy
  • Learn how to rearrange the EPE formula to solve for spring compression (x)
  • Explore examples of spring compression calculations in physics problems
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators seeking to clarify concepts related to energy conservation and spring dynamics.

mksnider77
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Homework Statement


A toy car with a mass of m=.079 kg crashes into a spring with constant k=69 N/m. If the car was going v=1.10 m/s, then how far will the spring compress?


Homework Equations


I think you could use the equation for Elastic Potential Energy but I'm not sure what to do with the mass or the velocity...

EPE= kv^2/2


The Attempt at a Solution


I really just don't know... I'm stuck and help would be greatly appreciated!
 
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Check the units on your EPE equation. Are you getting Joules (energy)?
 

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