Calculating Spring Constant of Bungee Cord

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SUMMARY

The discussion focuses on calculating the spring constant of a bungee cord for a jumper with a mass of 77.0 kg who oscillates after jumping. The jumper's period of oscillation is determined to be 6 seconds, derived from the total time of 48 seconds for 8 oscillations. Using the formula T = 2π√(m/k), the spring constant (k) is calculated to be 8.94 N/m. Participants confirm the method is correct and encourage showing calculations for verification.

PREREQUISITES
  • Understanding of Hooke's Law (F = -kx)
  • Familiarity with the formula for the period of oscillation (T = 2π√(m/k))
  • Basic knowledge of mass and weight concepts
  • Ability to perform algebraic manipulations to solve for variables
NEXT STEPS
  • Review the derivation of the period formula for oscillating systems
  • Explore the effects of mass on spring constant calculations
  • Investigate real-world applications of spring constants in bungee jumping
  • Learn about energy conservation in oscillatory motion
USEFUL FOR

Physics students, engineering students, and anyone interested in mechanics and oscillatory motion will benefit from this discussion.

HHippo
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Homework Statement


A bungee jumper with a mass of 77.0kg, jumps from a high bridge. He just touches the water in the river below and after reaching this lowest point, he oscillates up and down, hitting the lowest point another 8 times in 48.0 seconds. Calculate the spring constant of the bungee cord.

Homework Equations


F = -kx
T = 2π√(m/k)


The Attempt at a Solution


I thought the period was 6 (48/8) and then used those two equations to solve for k. Got 8.94 but I am not sure if I did it right...
 
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Hi HHippo, welcome to PH.
Will you please show your calculations?
 
You know the period and mass you can solve for the spring constant directly from the period equation. Check your math.
 
method seems correct show your calculations
 

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