A bungee jumper with a mass of 77.0kg, jumps from a high bridge. He just touches the water in the river below and after reaching this lowest point, he oscillates up and down, hitting the lowest point another 8 times in 48.0 seconds. Calculate the spring constant of the bungee cord.
F = -kx
T = 2π√(m/k)
The Attempt at a Solution
I thought the period was 6 (48/8) and then used those two equations to solve for k. Got 8.94 but I am not sure if I did it right...