Calculating Star Surface Emission at Different Temperatures | Physics Question

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The discussion revolves around calculating the power emitted by a star's surface as its temperature changes from 1000 degrees Kelvin to 900 degrees Kelvin, utilizing concepts from thermodynamics and radiation laws.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of the Stefan-Boltzmann Law and question how to properly utilize it in the context of the problem. There are also inquiries about the original poster's understanding and efforts in solving the problem.

Discussion Status

The discussion is ongoing, with participants providing guidance on the principles involved and encouraging the original poster to clarify their understanding. There is no explicit consensus yet, as various interpretations and approaches are being explored.

Contextual Notes

Participants note the importance of adhering to forum guidelines, which emphasize the need for showing work and understanding rather than simply receiving answers. There is also mention of the original poster's confusion and the merging of multiple threads due to repeated postings.

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If a star has a surface temperature of 1000 degrees Kelvin and emits 500,000 watts of each square-meter of surface area, how much power does each square-meter of its surface area emit after it has cooled to 900 degrees Kelvin?
 
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Have you any thoughts on the question? Which law do you think we should use?
 
If a star has a surface temperature of 1000 degrees Kelvin and emits 500,000 watts of each square-meter of surface area, how much power does each square-meter of its surface area emit after it has cooled to 900 degrees Kelvin?
 
Stephen-Boltzmann's Law i guess, but i couldn't figure out how? please help if u have any idea
 
Well you could start by writing down the Stephen-Boltzmann law and identifying what all the symbols mean...
 
Double posting isn't going to get your thread answered any quicker, I've already answered your other thread.
 
Thanks, am a kind of confused.
 
it may be easy for u to answer, so please help me?
 
Yarka said:
it may be easy for u to answer, so please help me?
I am trying to help you. The guidelines here at PF prevent us from providing solutions to problems, they also require that you show your efforts and that we guide you through the problem rather than just handing you the solution on a plate.
 
  • #10
ok. this is what i have= v/t=pi*P*D^4/128*L*Visc.

so 500,000=3.14*100*1000/128*L
Am i right?
 
  • #11
Two different threads have been merged because the OP made multiple postings.

Zz.
 

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