- #1

a.mlw.walker

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There is a cyclist rolling but not peddelling, so friction will eventually cause him to stop. You don't know a start speed, but Every 10 metres a time reading is taken to see how long it took him to travel that last ten metres so an acceleraton can be calculated

relative to when readings were taken:

0 - 10m : 2.5seconds

10 - 20m : 3.5 seconds

How do I work out how many metres he will travel?

Can I do a = [(distance/time1)-(distance/time2)]/total time

i.e [10/2.5 - 10/3.5]/(2.5 + 3.5)

= acceleration of -0.19 metres/second^2

Is this correct?