Calculating Sums of Infinite Series for Nille

Click For Summary
SUMMARY

The discussion focuses on calculating the sums of specific infinite series, particularly the series \sum_{n=0}^\infty\left(\frac{n+5}{5n+1}\right)^n and \sum_{n=0}^\infty\frac{\cos n\pi}{1+n^2}. The first series converges to approximately 2.5747, while the second series converges to \frac{1}{2}\left(1+\pi{\rm csch}(\pi)\right), where csch(z) denotes the hyperbolic cosecant function. The discussion highlights the lack of a general method for summing infinite series and emphasizes the importance of convergence analysis and Taylor series in deriving these sums.

PREREQUISITES
  • Understanding of infinite series and convergence
  • Familiarity with geometric series and their summation
  • Knowledge of hyperbolic functions, specifically csch(z)
  • Basic concepts of Taylor series and their applications
NEXT STEPS
  • Study the properties of convergence for infinite series
  • Learn how to derive sums using Taylor series expansions
  • Explore hyperbolic functions and their applications in series summation
  • Investigate numerical methods for approximating sums of infinite series
USEFUL FOR

Mathematicians, students studying calculus, and anyone interested in advanced series summation techniques.

nille40
Messages
34
Reaction score
0
Hi all!
I was wondering which method one should use to find the actual sum of an infinite series. I know how to find the sum of a geometric series (if it converges), but how could I find the sum for, for instance
<br /> \sum_{n=0}^\infty\left(\frac{n+5}{5n+1}\right)^n<br />

I know that it converges, and the sum appears to be 2. But how can I calculate this?

Or how about
<br /> \sum_{n=0}^\infty\frac{\cos n\pi}{1+n^2}<br />

Thanks in advance,
Nille
 
Physics news on Phys.org
There is no general method for determining the sum of an infinite series.
 
What if we try to find the sum to n terms and then taking lim n\rightarrow\infty
 
The answer to the first one is 2.5746952396343726343 Hope that will help
 
Last edited:
The second one is a defined convergent series:

\sum_{n=0}^\infty\frac{\cos n\pi}{1+n^2}=\frac12\left(1+\pi{\rm csch}(\pi)\right)

where csch(z) gives the hyperbolic cosecant of z, or in other words: csch(z)=1/sinh(z).
 
Last edited:
How You guys reach this conclusions I have read a little about convergence and divergence but don't know how you summed up the series
 
Originally posted by nille40
<br /> \sum_{n=0}^\infty\frac{\cos n\pi}{1+n^2}<br />

This one does not involve hyperbolic trig functions.

Taylor series.
 
laura: would you mind explaining further? Since the sum, as written, is clearly not a Taylor series, do you mean that it can be converted to one and then summed? If so, how? It's certainly not obvious to me!
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K