Calculating Temperature Increase from Energy Produced by a 60-Watt Bulb

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Discussion Overview

The discussion revolves around calculating the temperature increase of water when energy from a 60-watt bulb is applied over a short duration. The focus is on the application of energy transfer concepts in a practical scenario involving a specific example.

Discussion Character

  • Homework-related, Mathematical reasoning

Main Points Raised

  • One participant questions their calculation of the temperature increase of 1 gram of water when exposed to energy from a 60-watt bulb for 2 seconds, arriving at a result of 29 degrees Celsius.
  • Another participant confirms the calculation is correct and encourages the use of formulae in the explanation.
  • A different participant admits to not knowing the formula and references an external site for guidance.
  • One participant provides the relevant equations for energy transfer and temperature change, suggesting that understanding these concepts may be challenging for those unfamiliar with them.

Areas of Agreement / Disagreement

There is a general agreement on the correctness of the initial calculation, but uncertainty exists regarding the understanding and application of the underlying formulas.

Contextual Notes

Some participants express limitations in their understanding of the concepts and formulas involved in energy transfer and temperature change.

Who May Find This Useful

Individuals interested in practical applications of energy transfer concepts, particularly in physics or engineering contexts, may find this discussion beneficial.

AngelShare
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I'm not sure I'm doing this correctly...

If all of the energy from a 60-watt bulb was put into 1 gram of water at room temperature for 2 seconds, how much would the temperature of the water increase?

I tried it using the example but I wanted to check my answer first.

60 * 2 = 120
120 / 4.1868

29 degrees Celsius?
 
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That's correct; nice work.

Don't be afraid to show the formulae you use, though.
 
Ah, that's good.:smile:

Actually, I don't know the formula. I was using the example on this site http://ippex.pppl.gov/interactive/energy/calorie.html" .
 
Last edited by a moderator:
[tex]P = \frac{\Delta E}{\Delta t} \Rightarrow \Delta E = P \Delta t[/tex]

[tex]\Delta E = mc \Delta T[/tex]

They're a little useless if you've never covered the concept, though, I suppose.
 
Last edited:

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