Calculating Temperature of Fuel-Air Mixture

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SUMMARY

The discussion focuses on calculating the temperature of a fuel-air mixture in a four-stroke cycle 1.6 L displacement engine operating at 2500 rpm. Given a heat transfer rate of 1.4 kW and a heat of vaporization of 350 kJ/kg, the final temperature of the air entering the cylinder is estimated to be 86.62°C, assuming complete vaporization of the fuel. The volumetric efficiency is noted as 0.85, and the air density is 1.06 kg/m³. The calculation involves determining the mass of air inducted and the change in temperature using specific heat capacities.

PREREQUISITES
  • Understanding of volumetric efficiency in internal combustion engines
  • Knowledge of heat transfer principles, specifically the rate of heat transfer
  • Familiarity with specific heat capacities and heat of vaporization
  • Basic calculations involving mass flow rates and temperature changes
NEXT STEPS
  • Learn about the impact of equivalence ratios on fuel-air mixtures
  • Explore the concept of heat transfer in intake manifolds
  • Study the effects of fuel properties on combustion efficiency
  • Investigate advanced thermodynamic cycles in spark-ignition engines
USEFUL FOR

Engineers, automotive technicians, and students studying thermodynamics or internal combustion engine design will benefit from this discussion, particularly those focused on optimizing fuel-air mixture calculations and engine performance.

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Homework Statement


In many spark-ignition engines, liquid fuel is added to the inlet air upstream of the inlet manifold above the throttle. The inlet manifold is heated to ensure that under steady-state conditions the fuel is vaporized before the mixture enters the cylinder.

At normal wide-open throttle operating conditions, in a four-stroke cycle 1.6 L (Vd) displacement four-cylinder engine, at 2500 rpm (N), the temperature of the air entering the carburetor is 40C. The heat of vaporization of the fuel in 350 kJ/kg and the rate of heat transfer to the intake mixture is 1.4 kW. Estimate the temperature of the inlet mixture as it passes through the inlet valve, assuming that the fuel is fully vaporized. The volumetric efficiency is 0.85. The air density is 1.06 kg/m^3 and cp for air is 1 kJ/kgK. You may neglect the effects of the heat capacity of the liquid and vapor fuel.

Homework Equations


Volumetric Efficiency: Ratio of the mass of air inducted into the cylinders to the mass of ambient air
\eta_v =\frac{m_a}{\rho_a V_d}=\frac{2 \dot{m_a}}{\rho_a V_d N}

Rate of Heat Transfer
\dot{Q} = \dot{m} c \Delta T

The Attempt at a Solution


Not 100% sure where to start.

Calculating the mass of air inducted into the cylinders is straightforward... I'm just not sure how to tie it all together.
 
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The mass of air inducted into the cylinders is

0.85(1.06 kg/m^3)(1.6 L)(1 m^3/1000 L)(1000 g/kg) = 1.44 g
 
Since

\dot{Q}_{air}=c_p \dot{m}_a \Delta T=c_p m_a \Delta T (\frac{N}{2}),

You can calculate the change in temperature of the air to be

\Delta T = 46.62 C

and thus the final temperature of the air is 86.62 C.

The problem says you can neglect the effects of the heat capacity of the liquid and vapor fuel, but how do I take the temperature of the fuel into account for the temperature of the mix?
 
Last edited:
No one has any input or ideas? Surely there's someone who can help me!
 
A friend helped me out earlier...

The fuel-air mixture is traveling through the inlet manifold toward the engine. The inlet manifold is heated so as to vaporize the fuel.

Assuming an equivalence ratio of 0.8 and a stoichiometric A/F of 14.4, one can calculate the mass of the fuel mixed with the air. Know the specific heat of vaporization of the fuel allows us to determine how much energy was absorbed by the fuel to vaporize. The rest of the energy was absorbed by the air.

The 86.62 C calculated before is the maximum value of the air during this process and assumes no fuel in the mix.
 

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