Calculating Tension & Acceleration of Stacked Blocks | Newton's Laws Homework

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SUMMARY

This discussion focuses on calculating the tension in a rope and the acceleration of stacked blocks under the influence of tension and friction. The bottom block has a mass of 2 kg and is subjected to a tension force of 20 N, while the top block has a mass of 1 kg and is connected to a wall. The coefficients of kinetic friction are 0.40 for both blocks. The solution involves applying Newton's Second and Third Laws to derive the equations for net forces and normal forces, which are essential for determining the frictional forces acting on the blocks.

PREREQUISITES
  • Understanding of Newton's Second Law of Motion
  • Knowledge of friction coefficients and their application
  • Ability to calculate normal forces in a stacked system
  • Familiarity with free-body diagrams for analyzing forces
NEXT STEPS
  • Learn how to derive normal forces in multi-block systems
  • Study the application of Newton's Laws in static and dynamic scenarios
  • Explore the calculations of frictional forces using coefficients of friction
  • Investigate the effects of tension in connected systems
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Students studying physics, particularly those focusing on mechanics, as well as educators and tutors looking for examples of applying Newton's Laws to real-world problems involving friction and tension.

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Homework Statement



There are two blocks, the bottom block with a mass of 2kg and a block with mass of 1 kg stacked on top of it. Block on bottom is being pulled to the right by a tension force of 20 N. The top block is connected to the left wall by a rope. The coefficients of kinetic friction are .40 on bottom and top of the 2kg block.

Q1) What is the tension in the rope holding block of 1kg
Q2) what is the acceleration of block of 2kg



Homework Equations



Newtons 2nd/3rd law.

The Attempt at a Solution



For part 1, i have attempted to set Fnet(2) = 20N (tension)- Ffriction(2 on ground) - Ffriction(1 on 2)
and then set Fnet(1) = 0 = -T + Ffriction(1 on 2)

I cannot find how to relate them. I know that the top block should stay stationary while the bottom block moves away, but I don't know what masses to use to calculate the normal forces.

I figure if I can get guided to the answer for part 1, part 2 might be solvable. Thanks for your help.
 
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NinjaChemist said:

The Attempt at a Solution



For part 1, i have attempted to set Fnet(2) = 20N (tension)- Ffriction(2 on ground) - Ffriction(1 on 2)
and then set Fnet(1) = 0 = -T + Ffriction(1 on 2)

I cannot find how to relate them. I know that the top block should stay stationary while the bottom block moves away, but I don't know what masses to use to calculate the normal forces.

Write the equations for the vertical force components. From those, you get the normal forces. Multiplying the normal forces with the coefficient of friction, the forces of friction are obtained.

ehild
 

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