Calculating Tension in a 6-kg Bucket Being Pulled Up by a String

AI Thread Summary
The discussion centers on calculating the tension in a rope pulling a 6-kg bucket of water at a constant speed. The correct tension is determined to be about 60 N, as the bucket is in equilibrium with no net acceleration. Some participants initially suggested that the tension could be 0 N, but this was clarified as incorrect since the bucket would fall without tension. The relevant equations, including ΣF=ma and T=ma+mg, were referenced to support the calculations. Overall, the consensus is that the tension in the rope is indeed 60 N.
1man
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Homework Statement


A 6-kg bucket of water is being pulled straight up by a string at a constant speed.

What is the tension in the rope?

about 42 N
about 60 N
about 78 N
0 N because the bucket has no acceleration.

Homework Equations


\SigmaF=ma
ma=T-mg
T=ma+mg

The Attempt at a Solution



I get about 60 but I want to be sure before I submit this answer. can someone please check my work to make sure i am right?
 
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No its 0N any constant acceleration is in equilibrium therefore the net force is equal to 0. W=FD W=0
 
im looking for the tension and the tension wouldn't be 0 because if it were the bucket would be falling
 
sorry should have read your question better 60N is right for the tension.
 
1man said:

Homework Statement


A 6-kg bucket of water is being pulled straight up by a string at a constant speed.

What is the tension in the rope?

about 42 N
about 60 N
about 78 N
0 N because the bucket has no acceleration.

Homework Equations


\SigmaF=ma
ma=T-mg
T=ma+mg

The Attempt at a Solution



I get about 60 but I want to be sure before I submit this answer. can someone please check my work to make sure i am right?

i say 60N aswell
 

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