Calculating Tension in a Stretched String Using Wave Speed

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SUMMARY

The discussion focuses on calculating the tension in a stretched string given its linear density of 0.00500 kg/m and a wave speed of 85 m/s. The relevant equation is v = √(F/(m/L)), where v is the wave speed, F is the tension, and m/L is the linear density. To find the tension, the equation must be rearranged to F = v² * (m/L). Substituting the provided values results in a tension of 36.125 N.

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  • Understanding of wave mechanics and wave speed
  • Familiarity with linear density concepts
  • Basic algebra for rearranging equations
  • Knowledge of tension in strings and its relation to wave properties
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Homework Statement



A string whose linear density is 0.00500 kg/m is stretched to produce a wave speed of 85 m/s. What tension was applied to the string.

Homework Equations



v=√(F/(m/L))


The Attempt at a Solution



v=0.00500 kg/m m/L= 85 m/s

I can't seem to re-arrange the equation properly or I am just using the wrong one to begin with.
 
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Before plugging in any numbers, use algebra to solve the v=√(F/(m/L)) formula for the tension F. [And it might help to treat the linear density (m/L) as its own variable. I'd call it μ, or maybe λ.]
 
Last edited:

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