Calculating Tension in a String with Mass & Torsion

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To calculate the tension in a vertical string with mass M attached and twisted by an angle theta, the tension can initially be expressed as T = mg. However, torsion must also be considered, as it introduces a torque that affects the system. Tension and torsion act at 90 degrees to each other, so they cannot simply be added together as linear forces. The relevant equations include the torque equation, which involves the torsional constant and angular displacement. A complete analysis requires considering both the linear forces and the torque applied to the mass to fully understand the dynamics at play.
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Homework Statement


if a vertical string hangs with mass M attached to its end and is twisted by angle (theta) then
what will be the tension in the string

2. relevant equations
T= mg

torque= torsional constant x angular displacement
3. attempt to solution

i am not able to start with solution but it seems that tension that is Mg and torsion must be added
 
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Sorry, jonny23, but PF isn't the Magic 8-Ball. There are three parts to the HW template and you have completed only the first part. You still must provide a listing of any equations you think are relevant to finding a solution, and then show some work actually leading up to a solution, even an incorrect one.
 
So you've applied the equation, come up with Mg as the answer, and are wondering what torsion has to do with it, right?
Consider the mass and the forces on it. What are they?
 
and tension and torsion would be 90 degrees right so i need to take vector sum
 
jonny23 said:
and tension and torsion would be 90 degrees right so i need to take vector sum
Torsion is a torque, not a linear force, so it doesn't really make sense to add them together.
Of the forces/torques exerted by the string on the mass, I would say that, by definition, the tension is the linear component acting along the string. On that basis, what does ##\Sigma F = ma## applied to the mass in the vertical direction tell you?

(To get a complete picture of the forces on the mass, bear in mind that something is applying a torque to the mass in order to twist the string.)
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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