sweetdaisy186
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The discussion focuses on calculating the tension in ropes supporting two 10 kg blocks in an elevator accelerating upward at 2 m/s². The correct formula for tension is derived from Newton's second law, resulting in T = mg + ma, where g is the acceleration due to gravity (9.81 m/s²) and a is the elevator's acceleration. Participants clarify that when the elevator accelerates upward, both gravitational and elevator forces act in the same direction, necessitating their addition to find the correct tension.
PREREQUISITESStudents in physics courses, educators teaching mechanics, and anyone interested in understanding dynamics in systems involving tension and acceleration.
Is the elevator going upward or downward?loudgrrl4_ever said:I actually have just about the same problem for an assignment at the moment. The numbers are different, but that doesn't really matter.
I am really stuck.
Since the masses are the same, I am using plain m. Since T=m*a for each rope respectivly, the tension for the top rope should be T=2m*g-2m*a or T=2m(g-a), similarly the tension for the bottom rope would be T=m(g-a).
The problem is, this isn't working.
I am obviously missing something. Any help would be appreciated.
Do the balance of forces in the mass. You have mg pulling down and T pulling up, The vectorial sum is ma in the up direction. So, T - mg = ma and T = mg + ma.loudgrrl4_ever said:The elevator is going upward. I don't understand why you would add them, however.
That is the correct answer, but since we have a test tomorrow, I want to be sure I understand it much more than get a point on a silly assignment.
Here's how it is playing out in my mind:
A block is being pulled on upwards directly by the elevator, and downwards by gravity. How does the tension use both of those forces in the same direction?
Thanks for your help :)