Calculating Tension in Cable Winch BD - Drawing Included

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SUMMARY

The discussion focuses on calculating the tension in cable winch BD, specifically when a 200 kg mass is attached to a pulley system. The gravitational force acting on the mass is calculated to be 1960 N (200 kg * 9.81 m/s²). Participants clarify that the tension in the winch may not equal the weight of the mass if the mass is accelerating, prompting further analysis of the forces involved in the system.

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  • Understanding of Newton's laws of motion
  • Basic principles of pulley systems
  • Knowledge of force calculations (F = m * g)
  • Familiarity with tension in cables and ropes
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Homework Statement


Find the Tension in cable winch BD, link to drawing below.

http://i960.photobucket.com/albums/ae86/seanrumsby/Prob3-47.jpg

Homework Equations


The mass fixed to the other end of the pulley is 200 kg.

The Attempt at a Solution


I was under the impression that if one side of the pulley pulled down with 1960 N (200 kg * 9.81 ms^-2) then the tension in the winch would be the same as well.
Can anyone shed some light on this?
 
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pigmy02 said:

Homework Statement


Find the Tension in cable winch BD, link to drawing below.

http://i960.photobucket.com/albums/ae86/seanrumsby/Prob3-47.jpg

Homework Equations


The mass fixed to the other end of the pulley is 200 kg.

The Attempt at a Solution


I was under the impression that if one side of the pulley pulled down with 1960 N (200 kg * 9.81 ms^-2) then the tension in the winch would be the same as well.
Can anyone shed some light on this?
Is the mass is accelerating? So the forces on the 200 kg mass sum to _____? What are the forces? If there was any difference in the tension of the rope along the rope, what would have to occur?

AM
 

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