Calculating Tension in Circular Motion

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SUMMARY

The discussion focuses on calculating the tension force acting on mass m2 in a circular motion scenario involving a whirlygig. Given the mass m1 of 324.0 g and mass m2 of 111.0 g, the tension is determined using the equation T = mxa + mxg. Since mass m1 remains stationary vertically, the acceleration a is zero, leading to the conclusion that the tension T equals the weight of mass m1, calculated as T = 0.324 kg x 9.8 m/s², resulting in a tension force of 3.1872 N.

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  • Understanding of Newton's laws of motion
  • Basic knowledge of circular motion dynamics
  • Familiarity with gravitational force calculations
  • Ability to manipulate equations involving mass and acceleration
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  • Study the principles of circular motion and centripetal force
  • Learn about tension in different physical systems
  • Explore the effects of friction in circular motion scenarios
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Homework Statement


A whirlygig is made by hanging a mass, m1 = 324.0 g, through a tube and then spinning another mass, m2 = 111.0 g around so that it forms a circle. When this happens the string makes a small angle with the horizontal as shown in the diagram. If this is done at a specific speed then m1 does not move up or down, for this question assume than m2 is moving at this speed. Also assume that there is no friction between the string and the tube.

What is the magnitude of the tension force acting on mass m2?

Homework Equations



T = mxa + mxg

The Attempt at a Solution


[/B]
Since it says that at this speed, m 1 will not move up or down, I'm assuming a is zero

therefore,

T = 0.324 x 9.8

Correct or incorrect?
 
Last edited by a moderator:
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Yes, that sounds right.
 

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