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Not sure what you are saying. Are you maintaining that there's no difference between the time-averaged force and the distance-averaged force?KurtWagner said:
Calculating the Average Force on a Meteor Upon Entering Jupiter's Atmosphere
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SUMMARY
The discussion centers on calculating the average force exerted on a meteor with a mass of 1 kg and an initial velocity of 20 km/s as it penetrates 100 km into Jupiter's atmosphere. The correct average force is determined to be 200,000 N, contrasting with initial calculations yielding 2,000 N. Participants emphasize the importance of using the work-energy principle, specifically the equation 1/2 mv^2 = F x, to solve for force when acceleration is not constant, as is the case in this scenario.
PREREQUISITES- Understanding of Newton's laws of motion
- Familiarity with the work-energy principle
- Knowledge of kinematic equations
- Ability to convert units (e.g., km to m)
- Study the work-energy theorem in detail
- Learn about variable acceleration and its implications in physics
- Explore the differences between average force over distance and average force over time
- Review unit conversion techniques for physics problems
Students studying physics, particularly those focused on mechanics and dynamics, as well as educators seeking to clarify concepts related to force and energy in non-constant acceleration scenarios.
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