Calculating the central temperature of the Sun using the ideal gas law

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The discussion focuses on calculating the central temperature of the Sun using the ideal gas law, specifically addressing challenges in determining central density (rho_c) and average density (rho). Participants suggest that it may be acceptable to assume a simple form for density as a function of radius, such as rho(r) = rho_c (1 - r/R). This approach allows for integration to derive an expression for mass in terms of radius and central density, facilitating the calculation of rho_c. The proposed method aims to yield a value for central density that is within an acceptable range for the problem at hand. Overall, the conversation emphasizes the need for assumptions in density modeling to progress with the calculations.
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Homework Statement
Assuming an ideal gas law with no radiation pressure, P = ρkT/µmH, find
an expression for T(r).
Given mu = 0.61 for the Sun (you can use the Sun’s mass and radius), what
is the central temperature of the Sun in this model?
Relevant Equations
See below
2.PNG
1.PNG


I derived the equation for P so I substituted that into this equation. I'm struggling with finding rho_c (central density) and rho.
Am I supposed to use the average density for rho (can calculate this since I know the radius of Sun and mass)? That still leaves the problem with the central density though.
 
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accalternata said:
Am I supposed to use the average density for rho (can calculate this since I know the radius of Sun and mass)? That still leaves the problem with the central density though.
It's hard to know you are supposed to do. This is not my area but (in the absence of other replies) how about this...

It may be acceptable to assume some simple form for ##\rho(r)##. For example (as used in section 5.1 of this link) ##\rho(r) = \rho_{centre} ( 1 -\frac rR)##.

You can then integrate to get an expression for ##M## in terms of ##R## and ##\rho_{centre}## and hence find a value for ##\rho_{centre}##. This should be in the right 'ball park' which (in the context of the question) is probably acceptable.
 
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My attempt: Initial total M.E = PE of hanging part + PE of part of chain in the tube. I've considered the table as to be at zero of PE. PE of hanging part = ##\frac{1}{2} \frac{m}{l}gh^{2}##. PE of part in the tube = ##\frac{m}{l}(l - h)gh##. Final ME = ##\frac{1}{2}\frac{m}{l}gh^{2}## + ##\frac{1}{2}\frac{m}{l}hv^{2}##. Since Initial ME = Final ME. Therefore, ##\frac{1}{2}\frac{m}{l}hv^{2}## = ##\frac{m}{l}(l-h)gh##. Solving this gives: ## v = \sqrt{2g(l-h)}##. But the answer in the book...

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