Calculating the dimension of intersection of two matrices

Click For Summary

Homework Help Overview

The discussion revolves around the intersection of two matrices in the context of linear algebra. The original poster presents two matrices, M1 and M2, and seeks to calculate the dimensions of their sum and intersection.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants question the meaning of "intersection of matrices," with some suggesting interpretations involving subspaces of matrices. There is a discussion about the notation used and the implications of different interpretations.

Discussion Status

Participants are exploring various interpretations of the problem, with some providing clarifications on matrix notation and the nature of the intersection. There is no explicit consensus on the correct interpretation, but several productive lines of questioning have emerged.

Contextual Notes

There is mention of the importance of specifying the field of numbers involved, as well as the notation for matrices, which may affect the understanding of the problem. The original poster's wording has led to multiple interpretations that remain unresolved.

Mutlu CELIKKOL
Messages
2
Reaction score
0
<Moderator's note: Moved from a technical forum and thus no template.>

I am at the beginners level of linear algebra and having problem of the intersection of matrices. Your kind help is much appreciated for the following question

Code:
Let\quad M1=\begin{Bmatrix} x & -x \\ y & z \end{Bmatrix},\quad M2=\begin{Bmatrix} a & b \\ -a & c \end{Bmatrix},\quad x,z,y,z\quad a,b,c\quad \in \quad F\\ calculate\quad the\quad following;\quad \\ a)\quad dim\quad M1+M2\\ b)\quad dim\quad M1\quad \cap \quad M2\\
 
Last edited by a moderator:
Physics news on Phys.org
What do you mean by the intersection of matrices? Do you mean ##\mathbb{R}\cdot \begin{bmatrix}x&-x\\y&z\end{bmatrix} \cap \mathbb{R}\cdot \begin{bmatrix}a&b\\-a&c\end{bmatrix}## or what is it?
 
fresh_42 said:
What do you mean by the intersection of matrices? Do you mean ##\mathbb{R}\cdot \begin{bmatrix}x&-x\\y&z\end{bmatrix} \cap \mathbb{R}\cdot \begin{bmatrix}a&b\\-a&c\end{bmatrix}## or what is it?
That is exactly what I mean
 
So you should start to compare them. You have ##a_{11}=-a_{12}## and ##a_{11}=-a_{21}##. What do you get from that?

And please post those kind of questions in the future in our homework section, including the use of the (automatically inserted) template!
 
fresh_42 said:
What do you mean by the intersection of matrices? Do you mean ##\mathbb{R}\cdot \begin{bmatrix}x&-x\\y&z\end{bmatrix} \cap \mathbb{R}\cdot \begin{bmatrix}a&b\\-a&c\end{bmatrix}## or what is it?
What does this notation mean? Particularly ##\mathbb{R}\cdot \begin{bmatrix}x&-x\\y&z\end{bmatrix}##?
 
It was just a suggestion of a possible interpretation, the straight line through the given matrix as subspace of ##\mathbb{M}(2,\mathbb{R})##.
 
fresh_42 said:
It was just a suggestion of a possible interpretation, the straight line through the given matrix as subspace of ##\mathbb{M}(2,\mathbb{R})##.
I'm even more lost now.

What is a "straight line through the given matrix"?
What is ##\mathbb{M}(2,\mathbb{R})##?
I'm familiar with notations such as ##\mathbb{M}_{2, 3}## or the like, for matrices with 2 rows and 3 columns, or ##\mathbb{M}_{m, n}##, for m x n matrices. In both examples, the field is unstated.
 
I like to note the field as it is often important here whether the reals, complex numbers or even a finite field is allowed. With only one index, the quadratic version is meant, so ##\mathbb{M}(2,\mathbb{R})## means all real ##2\times 2## matrices. They build a vector space and one matrix, as given by the OP is a vector therein. Thus there is also a line through this vector and the zero matrix, which defines a one dimensional subspace. And the intersection is a point in this space.

Another possibility would have been ##\begin{bmatrix}x&-x\\y&z\end{bmatrix} = \left\{ \begin{bmatrix}a&b \\ c&d\end{bmatrix} \in \mathbb{M}(2,\mathbb{R}) \, : \, b=-a \right\}## in which case we get a three dimensional subspace.

Both are possible and the wording in post #1 doesn't tell. I used the line interpretation as it was easy to type. My real goal was to provoke a clarification.
 
  • Like
Likes   Reactions: SammyS

Similar threads

  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 19 ·
Replies
19
Views
3K
  • · Replies 1 ·
Replies
1
Views
4K