Calculating the Efficiency of a Transformer for a Small Appliance

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SUMMARY

The efficiency of a transformer for a small appliance with an input of 110 V and 6.4 W, and an output of 8.9 V at 270 mA is calculated using the formula: efficiency = (power out * 100) / (power in). The output power is determined to be 2.43 W (8.9 V * 0.270 A). Therefore, the efficiency of the transformer is approximately 38.03%. This calculation assumes ideal conditions without accounting for losses such as heat generation.

PREREQUISITES
  • Understanding of electrical power calculations (P = I * V)
  • Familiarity with transformer specifications and operation
  • Knowledge of basic electrical units (voltage, current, wattage)
  • Concept of efficiency in electrical devices
NEXT STEPS
  • Research the impact of transformer losses on efficiency
  • Learn about different types of transformers and their applications
  • Explore methods to improve transformer efficiency
  • Study the principles of electrical power distribution systems
USEFUL FOR

Electrical engineering students, appliance designers, and anyone involved in the design or analysis of transformers and their efficiency.

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Homework Statement



The specifications of a transformer for a small appliance read "Input: 110 V, 6.4 W" and "Output: 8.9 V, 270 mA". What is the efficiency of this transformer?

Homework Equations



P = I * V

V = I * R

The Attempt at a Solution



6.4 W / (8.9*(270*.001)) ---> I think this is wrong

I am just not sure how the voltage drop of the transformer would affect the power output...
 
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Your reasoning is absolutely correct, voltage drop theoretically shouldn't affect the power output, but in theory we assume that there is no losses, no heat generated etc.
Thus when such a question pops up (power out)*100/(power in ) will give you the efficiency.
 

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