1. The problem statement, all variables and given/known data A pair of power transmission lines each have 0.68-Ω resistance and carry 650 Amp. If the primary voltage of the 10:1 step-up transformer is 4.6 kV, calculate the input voltage of the step-down transformer at the other end. 2. Relevant equations P=IV V=IR IpVp = IsVs 3. The attempt at a solution I recognized that when the current passes through the primary transformer it will increase, so I used V = IR and rearranged to I = V/R = (4600)/(2(0.68)) = 3382.35A I don't know how to proceed afterwards because if I try to solve for voltage I receive 4600 which is equal to the primary transformer, and cannot be the case because this is a step down transformer.