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ilovejava

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## Homework Statement

A pair of power transmission lines each have 0.68-Ω resistance and carry 650 Amp. If the primary voltage of the 10:1 step-up transformer is 4.6 kV, calculate the input voltage of the

**step-down transformer**at the other end.

## Homework Equations

P=IV

V=IR

I

_{p}V

_{p}= I

_{s}V

_{s}

## The Attempt at a Solution

I recognized that when the current passes through the primary transformer it will increase, so I used V = IR and rearranged to I = V/R = (4600)/(2(0.68)) = 3382.35A I don't know how to proceed afterwards because if I try to solve for voltage I receive 4600 which is equal to the primary transformer, and cannot be the case because this is a step down transformer.