Calculating the field strength of an alternating magnetic field

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SUMMARY

The discussion focuses on calculating the magnetic field strength of an alternating magnetic field generated by a solenoid copper coil with specific parameters: a length of 7 cm, 5 turns, a radius of 0.75 cm, an applied current of 145 V, a current of 0.73 A, and a frequency of 1.10 MHz. Participants emphasize the importance of using consistent units, particularly converting the length from centimeters to meters and ensuring current is in amps for accurate calculations. The correct formula for calculating the magnetic field strength in kA/m is crucial for resolving the user's issue.

PREREQUISITES
  • Understanding of solenoid magnetic field calculations
  • Familiarity with unit conversions (cm to m, V to A)
  • Knowledge of alternating current (AC) principles
  • Basic grasp of electromagnetic theory
NEXT STEPS
  • Research the formula for calculating magnetic field strength in solenoids
  • Learn about unit conversion techniques for electrical parameters
  • Explore the effects of frequency on magnetic fields in AC circuits
  • Study the principles of electromagnetism related to solenoids
USEFUL FOR

Electrical engineers, physics students, and anyone involved in designing or analyzing solenoid-based magnetic systems will benefit from this discussion.

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I have a solenoid copper coil 7 cm lengths, 5 turns, r =0.75; applied current 145 V; 0.73 A; frequency 1.10 MHz and I'm still not able to calculate the magnetic field strength in kA/m. Can you help me?

I tried a number of formulas, but I just don't get it. :confused:
Please point me in the right direction.
 
Last edited:
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Well, what were the formulas you tried?

Also, did you pay attention to units? Note that the length is given in cm, and current in amps, but the units of the answer kA per metre.
 

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