Calculating the Integral of (cos x)^2: Possible or Impossible?

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SUMMARY

The integral of (cos x)^2 is calculable using the half-angle identity, which transforms the integral into a more manageable form. Specifically, the half-angle formula states that cos^2(x) can be expressed as (1 + cos(2x))/2. This allows the integral to be split into two parts: the integral of 1/2 dx and the integral of cos(2x) dx, leading to the final solution of x/2 + (sin(2x)/4) + C. The discussion highlights the importance of using trigonometric identities for solving integrals effectively.

PREREQUISITES
  • Understanding of trigonometric identities, specifically half-angle and double-angle formulas.
  • Familiarity with integral calculus, particularly techniques for integrating trigonometric functions.
  • Knowledge of the Euler's formula for complex numbers and its application in trigonometric functions.
  • Ability to manipulate algebraic expressions involving trigonometric functions.
NEXT STEPS
  • Study the half-angle identities in detail to understand their applications in integration.
  • Learn about the double-angle formulas and their role in simplifying trigonometric integrals.
  • Explore the use of Euler's formula in calculus, particularly in integrating trigonometric functions.
  • Practice solving integrals of trigonometric functions using various techniques, including substitution and identities.
USEFUL FOR

Students of calculus, mathematics educators, and anyone looking to deepen their understanding of integrating trigonometric functions.

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Do anyone have an idea how to calculate integral of (cos x)^2 ? Or is it even possible? I tried some substitutions and/or rules of trigonometry, like cosxcosx+sinxsinx=1, but it didn't help. Thank you!
 
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cos2x+sin2x=1
cos2x-sin2x=cos2x
Therefore cos2x=(1+cos2x)/2

I'll let you finish.
 
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Thank you. :) integral (cos x)^2 dx
 
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dont you have to use half angle identities to get integral of cos^2 ?
 
No, double angle formulas as mathman said.
 
an easy way to remember the solution to this common integral, when integrating over a whole period:

cos^2 x + sin ^2 x =1
\int cos^2 x = \int sin^2 x
, at least when you integrate over a whole period

\int cos^2 x + \int sin^2 x = length of a period

so the integral gives length of a period divided by 2
 
Why does this thread have over 16,000 views?

edit: Oh, it's four years old.
 
First use the half-angle formula to change the cos(x)^2 to (1+cos(2x))/2...
This will allow you to break the integral into two separate problems much easier to solve
integral{ 1/2dx + integral{ cos(2x)dx
Then you will have x/2 + (sin(2x)/2) + C
 
What the, that's not even correct. If you're going to revive a 5-year old thread, at least make sure you don't have arithmetic errors.
 
  • #10
sin(2x)/4 ;)
 
  • #11
use the euler's formula

cos x= [e^ix+e^-ix ]
[-------------]
[ 2 ]
 
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  • #12
http://www.5min.com/Video/An-Introduction-to-Integrals-with-Powers-of-Sine-and-Cosine-169056088

Why doesn't the student, after nearly 6 years of unsuccessfully attempting this crazy integral, try a visual aid?
 
  • #13
This is crazy. The very first reply, post #2, answered the question. Six years ago!
 
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