Calculating the Invariant Interval for Two Events

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SUMMARY

The discussion centers on calculating the invariant interval for two events in the context of special relativity. Given the events defined by ct1 = 3 m, x1 = 2 m, ct2 = 5 m, and x2 = 6 m, the time difference is computed as t2 - t1 = (2/3) * 10-8 s. The calculation of the invariant interval is based on the formula (Δs)2 = +c2(t2 - t1)2 - (x2 - x1)2 - (y2 - y1)2 - (z2 - z1)2. The discussion highlights the importance of understanding the relationship between time and space in different reference frames.

PREREQUISITES
  • Understanding of special relativity concepts
  • Familiarity with the invariant interval formula
  • Basic knowledge of unit conversions in physics
  • Comprehension of reference frames in physics
NEXT STEPS
  • Study the derivation of the invariant interval in special relativity
  • Learn about Lorentz transformations and their applications
  • Explore the concept of time dilation and length contraction
  • Investigate the implications of different reference frames on observed events
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Students of physics, particularly those studying special relativity, as well as educators looking to clarify concepts related to time and space intervals in different reference frames.

joriarty
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Homework Statement



Consider two events
ct_{1}\; =\; 3\; m,\; x_{1}\; =\; 2\; m,\; ct_{2}\; =\; 5\; m,\; x_{2}\; =\; 6m

  1. What is the time difference between the two events?
  2. Find a reference frame for which the time difference is the negative of the time difference in the original frame.
  3. Calculate the invariant interval \left( \Delta s \right)^{2}=+c^{2}\left( t_{2}-t_{1} \right)^{2}-\left( x_{2}-x_{1} \right)^{2}-\left( y_{2}-y_{1} \right)^{2}-\left( z_{2}-z_{1} \right)^{2} in both frames.

Homework Equations



The Attempt at a Solution



I honestly don't have any idea what the first question is actually asking. How can I calculate a time difference when I am only given these distance figures with no velocities? It seems like an extremely poorly worded question.
 
Last edited:
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joriarty said:

Homework Statement



Consider two events
ct_{1}\; =\; 3\; m,\; x_{1}\; =\; 2\; m,\; ct_{2}\; =\; 5\; m,\; x_{2}\; =\; 6m

  1. What is the time difference between the two events?
  2. Find a reference frame for which the time difference is the negative of the time difference in the original frame.
  3. Calculate the invariant interval \left( \Delta s \right)^{2}=+c^{2}\left( t_{2}-t_{1} \right)^{2}-\left( x_{2}-x_{1} \right)^{2}-\left( y_{2}-y_{1} \right)^{2}-\left( z_{2}-z_{1} \right)^{2} in both frames.

Homework Equations



The Attempt at a Solution



I honestly don't have any idea what the first question is actually asking. How can I calculate a time difference when I am only given these distance figures with no velocities? It seems like an extremely poorly worded question.
The first question is just a unit conversion. What does c stand for?
 
Well c = 3*108 ms-1. So t1 = 1*10-8 s and t2 = (5/3)*10-8 s.

I guess assuming these are both observed from a laboratory frame of reference then the time difference is just t2 - t1 = (2/3)*10-8 s?

It was a simple question, but the obscure way in which it was asked threw me off. Typical me, struggling with the simple stuff but I can much more easily understand the complicated things :smile: Thank you for your help. Hopefully I can do the other two problems myself!
 

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