Calculating the magnetic moment of an electron

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SUMMARY

The discussion focuses on calculating the magnetic moment of an electron modeled as a uniformly charged sphere with mass density ρ_m and charge density ρ_e. The relevant parameters include the electron mass (m_e = 9.109 x 10^-31 kg), charge (e = 1.602 x 10^-19 C), and radius (r_e), with rotation frequency ω about the z-axis. The magnetic moment is derived using the formula m = (1/2) ∫ r × J(r) dτ, where J is the current density. Participants noted challenges in expressing J in terms of ω and suggested alternative approaches to solve the problem.

PREREQUISITES
  • Understanding of classical electromagnetism concepts, particularly magnetic moments.
  • Familiarity with vector calculus, especially integration of vector fields.
  • Knowledge of charge and mass density calculations.
  • Basic understanding of rotational dynamics and angular frequency.
NEXT STEPS
  • Study the derivation of magnetic moments in classical electromagnetism.
  • Learn about vector calculus techniques for integrating vector fields.
  • Explore the implications of charge density and current density in electromagnetic theory.
  • Investigate alternative models for calculating magnetic moments, such as using quantum mechanics.
USEFUL FOR

This discussion is beneficial for physics students, particularly those studying electromagnetism, as well as educators and researchers interested in advanced topics related to magnetic moments and electron behavior.

PsychoDash
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Homework Statement



Assume that an electron is a sphere of uniform mass density
\rho_m=\frac{m_e}{\frac{4}{3} \pi r_e^3}, uniform charge
density \rho_e=\frac{-e}{\frac{4}{3} \pi r_e^3}, and
radius r_e rotating at a frequency \omega
about the z-axis. m_e=9.109*10^{-31} kg and
e=1.602*10^{-19} C

Using the formula \vec{m}=\frac{1}{2} \int \vec{r} \times<br /> \vec{J(\vec{r})} d\tau, compute the magnetic moment of this
electron. Your answer should depend on e, \omega and
r_e

Homework Equations



Given above.

The Attempt at a Solution



Ok, so I know that in general, \vec {J}=\rho_e \vec {v}. I'm not sure how to proceed from here since writing J in terms of omega yields \vec {J}=\frac {\rho_e \omega}{\vec {r}}. I've always heard that dividing by a vector is not strictly defined in a math sense. Either I'm not approaching this in the right way, or putting that funkiness into the cross product above yields some magnificence that I am, as of now, incapable of seeing.

Help will be greatly appreciated.
 
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yeah integrating vectors gets really really hairy, when i get home i will help you out. There is a way to define some new quantity "C" per-say and it makes it easier

Unless someone helps you first
 
The assignment has already been turned in. I ended up just not using the given formula. Got the correct answer, even if not really in the correct way. Thanks though.
 

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