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Calculating the magnitude of the force on an electron

  1. Mar 22, 2009 #1
    1. The problem statement, all variables and given/known data
    an electron travels at a speed of 2.0X10^4 m/s threw a uniform magnetic feild whose magnitude is 1.2x10^4 T. what is the magitude of of the force on the electron if its velocity vector and magnetic vector are
    a)parralel
    b)45degrees
    c)parralel


    2. Relevant equations
    Fmax=QVB
    F=QVSintheta



    3. The attempt at a solution
    for a i got .0012
    b i got 16.47N
    c i got 0
    i think i am using the wrong equations
     
  2. jcsd
  3. Mar 22, 2009 #2

    rock.freak667

    User Avatar
    Homework Helper

    well using the right hand rule, which says that the current,force and magnetic field are at 90 degrees to each other, you'd see that if the velocity direction is parallel to the magnetic field you have no force.

    Use th equation F=BQvsin[itex]\theta[/itex] to get the force for part b
     
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