Calculating the magnitude of the force on an electron

[jaa72]

Homework Statement

an electron travels at a speed of 2.0X10^4 m/s threw a uniform magnetic field whose magnitude is 1.2x10^4 T. what is the magitude of of the force on the electron if its velocity vector and magnetic vector are
a)parralel
b)45degrees
c)parralel

Homework Equations

Fmax=QVB
F=QVSintheta

The Attempt at a Solution

for a i got .0012
b i got 16.47N
c i got 0
i think i am using the wrong equations

 

[rock.freak667]

well using the right hand rule, which says that the current,force and magnetic field are at 90 degrees to each other, you'd see that if the velocity direction is parallel to the magnetic field you have no force.

Use th equation F=BQvsin$\theta$ to get the force for part b