Calculating the moment of inertia in a pulley system

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SUMMARY

The discussion focuses on calculating the moment of inertia for a pulley system involving a solid disk reel and a suspended mass. The moment of inertia formula used is I = (1/2)MR², where M is the mass of the disk and R is its radius. The factor of one-half arises from the geometric properties of a solid disk, which is crucial for accurate calculations in rotational dynamics. Understanding this concept is essential for solving related problems in physics, particularly those involving rotational motion.

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  • Understanding of rotational dynamics
  • Familiarity with the moment of inertia concept
  • Knowledge of basic physics equations related to motion
  • Ability to apply energy conservation principles
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  • Study the moment of inertia for various geometric shapes
  • Learn about rotational motion equations and their applications
  • Explore energy conservation in mechanical systems
  • Practice solving problems involving pulleys and rotating objects
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Students studying physics, particularly those focusing on mechanics and rotational dynamics, as well as educators looking for examples of practical applications of moment of inertia in real-world scenarios.

mldavis086
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Homework Statement



An object with a mass of m = 5.10 kg is attached to the free end of a light string wrapped around a reel of radius R = 0.250 m and mass M = 3.00 kg. The reel is a solid disk, free to rotate in a vertical plane about the horizontal axis passing through its center. The suspended object is released from rest 6.00 m above the floor. Determine
(a) the tension in the string,
(b) the acceleration of the object, and
(c) the speed with which the object hits the fl oor.
(d) Verify your answer to (c) by using the isolated system (energy) model.

Homework Equations





The Attempt at a Solution



I don't expect you to answer the whole question but just this part would be great!

When calculating the moment of inertia, I have the formula to be I = Ʃ m*r^2

They show how to get the answer in the book but I don't understand it. When they calculate the moment of inertia, they have (1/2)(3)(0.25)^2

Where did the half come from? This is a new chapter in the book and I'm not sure I even really get what the moment of inertia is. If anyone can help me it would be greatly appreciated
 
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hi mldavis086 ! :smile:
mldavis086 said:
… The reel is a solid disk …

When calculating the moment of inertia, I have the formula to be I = Ʃ m*r^2

They show how to get the answer in the book but I don't understand it. When they calculate the moment of inertia, they have (1/2)(3)(0.25)^2

Where did the half come from?

ah, you need to learn the moment of inertia of the common shapes (see eg http://en.wikipedia.org/wiki/List_of_moments_of_inertia) :wink:

for a disc (ie a cylinder), about its axis, it's 1/2 mr2 :smile:
 
That's great. Thanks!
 

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