Calculating the Moment of Inertia of a loaded flywheel

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Discussion Overview

The discussion focuses on calculating the moment of inertia of a loaded flywheel in order to determine the necessary torque for its operation. Participants explore the implications of different mass components and their contributions to the moment of inertia, as well as the relationship between torque and load dynamics.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant inquires about using the formula I=1/2 * M * R^2 for calculating the moment of inertia and whether to use the mass of the flywheel alone or the entire assembly including the load.
  • Another participant suggests that the formula is appropriate for a solid cylinder but emphasizes the need to consider the inertia of the axle and motor as well.
  • There is a question regarding whether the mass used in the moment of inertia calculation should include the load that will be moving vertically, with a clarification that the load's mass should be considered at a distance R from the center axis.
  • A participant provides a detailed description of the assembly and asks for clarification on the distance R in relation to the load's center of mass.
  • Another participant confirms that R should be measured from the center of the flywheel to the center of the wire carrying the load.

Areas of Agreement / Disagreement

Participants express uncertainty about the appropriate mass to use in the moment of inertia calculation and whether to include the entire assembly or just the flywheel. There are multiple competing views regarding the contributions of different components to the moment of inertia and torque calculations, indicating that the discussion remains unresolved.

Contextual Notes

Participants mention the need to account for various components such as the axle and motor, and there are references to the load's movement affecting torque but not inertia. The discussion highlights the complexity of the calculations involved and the importance of precise definitions and assumptions.

wakadarc
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Hi,

I need to calculate the moment of inertia of this flywheel so I can calculate the torque I need.

T= I*alpha

Attached is an image of the flywheel the cam follower that will be attached to the shaft (left shaft in this picture). When calculating the Moment of Inertia, what mass do I use? The mass of the cam follower will be atleast 100KG (another load will be on top of that).

Can I just use I=1/2 * M*R^2

I will need a torque larger than what is required to rotate the loaded flywheel as the load will be variable.

Thanks,
 

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wakadarc said:
Can I just use I=1/2 * M*R^2
As for your purpose, the formula will be close enough. It's the formula for a solid cylinder ( there is a groove at the outside of your wheel ).

The exact formula/definition is

I = ∫ r2⋅dm.

Remember the inertia of the axle and the motor, assuming they are rotating as well.

T = I * dω/dt
 
Last edited:
Thanks but for the equation

I=MR^2 do I use the mass of the flywheel (in KG) or the entire assembly? (The cam shaft plus the load on top of it aka 150 KG). The flywheel will need to rotate with that load which will move vertically up and down.

Thanks,
 
wakadarc said:
I=MR^2 do I use the mass of the flywheel (in KG) or the entire assembly?
As for the rotating parts ( wheel+axle+motor ) you must calculate the inertias individually, then add these inertias.

As for the load, you must place its mass at a distance = R from the center axis. As for the inertia it dosn't matter if the load is moving vertically or horizontally, but when the load is moved vertically, it will result in a torque, which has nothing to do with inertia.

Tload = m*g*R, even if dω/dt = 0.
 
Sorry just so we are on the same page I made a side view of the entire assembly. So the rectangle on the far right is the fly wheel. The horizontal shaft connected to it is the offset shaft (that will cause the platform (the other horizontal rectangle) to move up andr e down. The cam (the rectangle with the X) is attached to the shaft. Finally the box on the very top is the load which is resting on the plat form. In this picture it would be moving in a circular motion but I used linear bearings so restrict it to vertical motion.

So for your equation Tload = m*g*R

the R would be from the center of the fly wheel to the center of mass of the box (load)?
 

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wakadarc said:
I made a side view of the entire assembly. So the rectangle on the far right is the fly wheel. The horizontal shaft connected to it is the offset shaft (that will cause the platform (the other horizontal rectangle) to move up andr e down. The cam (the rectangle with the X) is attached to the shaft. Finally the box on the very top is the load which is resting on the plat form. In this picture it would be moving in a circular motion but I used linear bearings so restrict it to vertical motion.
Sorry, I'm a kind of an extra terrestrial here ( don't understand technical english well ), so somebodies assistance needed.

wakadarc said:
R would be from the center of the fly wheel to the center of mass of the box (load)?
R is the distance from the center of the wheel to the center of the wire carrying the load.
 

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