Calculating the Net Force of a Bouncing Ball

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SUMMARY

The average net force acting on a rubber ball with a mass of 0.08 kg, which strikes the floor at 10 m/s and rebounds at 8 m/s, is calculated to be 28.8 N. This calculation is derived from the change in momentum, which is 1.44 kg·m/s, divided by the contact time of 0.05 seconds. An initial calculation using kinetic energy resulted in an incorrect force of 80 N, highlighting the importance of using the correct formula for average force.

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  • Understanding of Newton's laws of motion
  • Familiarity with the concepts of momentum and force
  • Knowledge of basic physics equations, specifically F = Δp/t
  • Ability to perform calculations involving mass, velocity, and time
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Homework Statement



a rubber ball mass of 0.08 kg bounces vertically on a concrete floor. the ball strikes the floor at 10 ms-1 and rebounds at 8 ms-1. The time in contact with the floor is 0.05 sec.
Calculate the average net force acting on the ball during the contact with the floor.

Homework Equations


E=F/t

F=0.5mv^2

The Attempt at a Solution



(0.5x0.08x10^2)/0.05
= 80N

I get a force of 80 N but to me it seems to much to be true... Help?
 
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You have to find the average force which is found by
F= (change in momentum)/time.
 
rl.bhat said:
You have to find the average force which is found by
F= (change in momentum)/time.

So change in momentum= 1.44 kgms-1

F=1.44/0.05
=28.8N

that seems more plausible Thanks for the help!
 

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