Calculating the number of terms in sequences

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To calculate the number of terms in the double summation \sum_{a=2}^k \sum_{b=a}^k \frac{1}{ab}, one must first recognize that this is not a sequence but a sum. The number of terms can be determined by expanding the inner and outer sums. Specifically, the "a-th" term has k - a + 1 terms, leading to the expression \sum_{a=2}^k (k + 1 - a). This can be simplified to (k - 1)(k + 1) minus the sum of integers from 2 to k. Understanding these calculations is essential for accurately determining the total number of terms in the summation.
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How does one calculate the number of terms in the sequence

\sum\limits_{a=2}^k \sum\limits_{b=a}^k of 1/(a*b).
 
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Cheung said:
How does one calculate the number of terms in the sequence

\sum\limits_{a=2}^k \sum\limits_{b=a}^k of 1/(a*b).
Is this what you're asking about?

$$ \sum_{a = 2}^k \sum_{b = a}^k \frac 1 {ab}$$

In any case, this is not a sequence, it's a sum (a double summation). To find how many terms, start by expanding the inner sum, and than expand the outer sum.
 
The "ath" term has k- a+ 1= k+1- a terms so there are \sum_{a= 2}^k (k+ 1- a) We can write that as \sum_{a= 2}^k (k+1)- \sum_{a= 2}^k a. Of course, \sum{a= 2}^k (k+1)= (k-1)(k+1). What is \sum_{a=2}^k a?
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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