Calculating the number of terms in sequences

  • Context: Undergrad 
  • Thread starter Thread starter Cheung
  • Start date Start date
  • Tags Tags
    Sequences Terms
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
2 replies · 2K views
Cheung
Messages
3
Reaction score
0
How does one calculate the number of terms in the sequence

\sum\limits_{a=2}^k \sum\limits_{b=a}^k of 1/(a*b).
 
Physics news on Phys.org
Cheung said:
How does one calculate the number of terms in the sequence

\sum\limits_{a=2}^k \sum\limits_{b=a}^k of 1/(a*b).
Is this what you're asking about?

$$ \sum_{a = 2}^k \sum_{b = a}^k \frac 1 {ab}$$

In any case, this is not a sequence, it's a sum (a double summation). To find how many terms, start by expanding the inner sum, and than expand the outer sum.
 
The "ath" term has k- a+ 1= k+1- a terms so there are [tex]\sum_{a= 2}^k (k+ 1- a)[/tex] We can write that as [tex]\sum_{a= 2}^k (k+1)- \sum_{a= 2}^k a[/tex]. Of course, [tex]\sum{a= 2}^k (k+1)= (k-1)(k+1)[/tex]. What is [tex]\sum_{a=2}^k a[/tex]?