Calculating the number of terms in sequences

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The discussion focuses on calculating the number of terms in the double summation $$ \sum_{a=2}^k \sum_{b=a}^k \frac{1}{ab}$$. It clarifies that this expression is not a sequence but a sum, and to determine the number of terms, one must expand both the inner and outer sums. The total number of terms can be expressed as $$\sum_{a=2}^k (k + 1 - a)$$, which simplifies to $$(k - 1)(k + 1)$$ after further manipulation.

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How does one calculate the number of terms in the sequence

\sum\limits_{a=2}^k \sum\limits_{b=a}^k of 1/(a*b).
 
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Cheung said:
How does one calculate the number of terms in the sequence

\sum\limits_{a=2}^k \sum\limits_{b=a}^k of 1/(a*b).
Is this what you're asking about?

$$ \sum_{a = 2}^k \sum_{b = a}^k \frac 1 {ab}$$

In any case, this is not a sequence, it's a sum (a double summation). To find how many terms, start by expanding the inner sum, and than expand the outer sum.
 
The "ath" term has k- a+ 1= k+1- a terms so there are [tex]\sum_{a= 2}^k (k+ 1- a)[/tex] We can write that as [tex]\sum_{a= 2}^k (k+1)- \sum_{a= 2}^k a[/tex]. Of course, [tex]\sum{a= 2}^k (k+1)= (k-1)(k+1)[/tex]. What is [tex]\sum_{a=2}^k a[/tex]?
 

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