Cheung
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How does one calculate the number of terms in the sequence
\sum\limits_{a=2}^k \sum\limits_{b=a}^k of 1/(a*b).
\sum\limits_{a=2}^k \sum\limits_{b=a}^k of 1/(a*b).
The discussion focuses on calculating the number of terms in the double summation $$ \sum_{a=2}^k \sum_{b=a}^k \frac{1}{ab}$$. It clarifies that this expression is not a sequence but a sum, and to determine the number of terms, one must expand both the inner and outer sums. The total number of terms can be expressed as $$\sum_{a=2}^k (k + 1 - a)$$, which simplifies to $$(k - 1)(k + 1)$$ after further manipulation.
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Is this what you're asking about?Cheung said:How does one calculate the number of terms in the sequence
\sum\limits_{a=2}^k \sum\limits_{b=a}^k of 1/(a*b).