Calculating the pH of 350L of Sulfuric Acid (H2SO4)

[Borek]

Can you write NaOH in dissociated form?

 

[chawki]

sure
NaOH ----> Na⁺ + OH^-

 

[Borek]

OK, now, what would happen when you add H⁺ to the mix?

H⁺ + Na⁺ + OH^- -> ?

 

[chawki]

i don't know...but why we will add H⁺

 

[Borek]

Why? Because the question is about reaction between H⁺ and OH^-. You have a solution of H⁺ and you add solution of OH^- (Na⁺ and SO₄^2- don't take part in the reaction, they are so called spectators).

What simple, electrically neutral molecule can be a product of reaction between H⁺ and OH^-? Try to guess, it is so simple you will hate yourself you have not realized it earlier.

 

[raviyank]

sulphuric has 2 protons.

so ph =-log(0.0004)

=-(log4-4)
=-(0.6021-4)
=3.3979

 

[raviyank]

1 hydrogen has 1 proton but in sulphuric there are 2 hydrogen

 

[Borek]

sulphuric has 2 protons.

so ph =-log(0.0004)

=-(log4-4)
=-(0.6021-4)
=3.3979

This is wrong, please reread the question.

And read forum rules, giving final answers is against them. Not to mention giving wrong final answers.

 

[chawki]

Hello Borek
please check this:

C_A*V_A=C_B*V_B
2*10^-4*350=m_B/40
m_B=2*10^-4*350*40 = 2.8g

That's it ?

 

[Borek]

2.8g of NaOH it is.

 

[chawki]

2.8g of NaOH it is.

Yay thank you Borek