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Calculating the pressure of a hailstone

  1. Jan 19, 2009 #1
    1. The problem statement, all variables and given/known data
    During a hailstorm , hailstones with an average mass of 2 g and a speed 15m/s strike a window pane at a 45 degree angle. The area of the window is .5 m^2 and the hailstones hit it at a rate of 30 per second. What average presure do they exert on the window? How does this compare to the pressure of the atmosphere?

    2. Relevant equations


    3. The attempt at a solution

    N/s=30 hailstones/sec
    m=2 grams

    P=m(-2vx)/([tex]\Delta[/tex]t))*N/A=(2e-3 kg)(-2(15)(cos 45 degrees)(30))/(second)/(.5 m^2)

    to compare the pressure of the hail stone to the pressure of the atmosphere, wouldn't I take the ratio of the pressure of the hailstone to the pressure of the atmosphere?
  2. jcsd
  3. Jan 19, 2009 #2


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    The pressure calculation looks ok to me. Sure, a ratio would be a good way to compare the two pressures.
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