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pentazoid

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## Homework Statement

During a hailstorm , hailstones with an average mass of 2 g and a speed 15m/s strike a window pane at a 45 degree angle. The area of the window is .5 m^2 and the hailstones hit it at a rate of 30 per second. What average presure do they exert on the window? How does this compare to the pressure of the atmosphere?

## Homework Equations

[tex]\overline{}[/tex]P=[tex]\overline{}[/tex]F/A=-m([tex]\Delta[/tex]v

_{x}/([tex]\Delta[/tex]t)/A

## The Attempt at a Solution

N/s=30 hailstones/sec

m=2 grams

[tex]\Delta[/tex]v

_{x}=v

_{x,final}-v

_{x,initial}=(-v

_{x}-v

_{x})=-2v

_{x}

P=m(-2v

_{x})/([tex]\Delta[/tex]t))*N/A=(2e-3 kg)(-2(15)(cos 45 degrees)(30))/(second)/(.5 m^2)

to compare the pressure of the hail stone to the pressure of the atmosphere, wouldn't I take the ratio of the pressure of the hailstone to the pressure of the atmosphere?