How Is the Average Pressure of Hailstones on a Window Calculated?

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SUMMARY

The average pressure exerted by hailstones on a window during a hailstorm can be calculated using the formula Pressure = Force/Area. In this scenario, hailstones with an average mass of 2g and a speed of 15m/s strike a windshield at a 45-degree angle and bounce off horizontally. The area of the window is 0.5m². The force exerted by the hailstones can be determined by analyzing the change in momentum, as the initial and final velocities differ, despite the speed remaining constant.

PREREQUISITES
  • Understanding of Newton's Second Law (Force = mass x acceleration)
  • Knowledge of momentum and its conservation
  • Familiarity with pressure calculations in physics
  • Basic trigonometry for angle calculations
NEXT STEPS
  • Study the concept of impulse and its relation to momentum change
  • Learn how to calculate pressure in different contexts, such as fluid dynamics
  • Explore the effects of angle on impact force calculations
  • Investigate real-world applications of pressure calculations in engineering
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This discussion is beneficial for physics students, educators, and anyone interested in understanding the dynamics of impact forces and pressure calculations in real-world scenarios.

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Homework Statement


During a hailstorm, hailstones with an average mass of 2g and a speed of 15m/s fall vertically down and strike a winshield angled at 45 degrees and bounce off at the same speed horizontally. The area of the window is .5m2 What is the average pressure they exert on the window?


Homework Equations





The Attempt at a Solution


So far this is what I've worked out:
Pressure = Force/Area
Force = ma but since there is no loss in velocity then that means that a=0 and the stones exert no force on the window?
 
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Can you relate force to the change in momentum?
 

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