MHB Calculating the Sixth Root of 3

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The discussion focuses on the calculation of the sixth root of 3, specifically addressing the incorrect interpretation of the expression involving cube roots. The correct approach involves using the property of exponents where the sum of exponents applies when bases are the same. The participants clarify that the sixth root of 3 can be expressed as 3^(1/6), and the calculation of cube roots leads to the conclusion that 3^(1/3) * 3^(1/3) equals 3^(2/3), not 3^(1/6). This highlights the importance of correctly applying exponent rules in mathematical expressions.

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mathdad
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Let cbrt = cube rootcbrt{3} x cbrt{3} =

(3)^(1/3) * (3)^(1/3)

3^(1/6) ir sixth root {3}

Correct?
 
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In general, you want to use the following rule:

$$\sqrt[3]{a}\cdot\sqrt[3]{b}=\sqrt[3]{ab}$$

Using exponents, we can get the same result:

$$a^c\cdot b^c=(ab)^c$$

Now, when the base is the same, we can simply add exponents:

$$a^b\cdot a^c=a^{b+c}$$

So, in the given expression, we may write:

$$\sqrt[3]{3}\cdot\sqrt[3]{3}=\sqrt[3]{3\cdot3}=\sqrt[3]{3^2}=3^{\frac{2}{3}}=3^{\frac{1}{3}+\frac{1}{3}}=3^{\frac{1}{3}}\cdot3^{\frac{1}{3}}=\sqrt[3]{3}\cdot\sqrt[3]{3}$$
 
MarkFL said:
In general, you want to use the following rule:

$$\sqrt[3]{a}\cdot\sqrt[3]{b}=\sqrt[3]{ab}$$

Using exponents, we can get the same result:

$$a^c\cdot b^c=(ab)^c$$

Now, when the base is the same, we can simply add exponents:

$$a^b\cdot a^c=a^{b+c}$$

So, in the given expression, we may write:

$$\sqrt[3]{3}\cdot\sqrt[3]{3}=\sqrt[3]{3\cdot3}=\sqrt[3]{3^2}=3^{\frac{2}{3}}=3^{\frac{1}{3}+\frac{1}{3}}=3^{\frac{1}{3}}\cdot3^{\frac{1}{3}}=\sqrt[3]{3}\cdot\sqrt[3]{3}$$

Great but is my answer wrong?
 
RTCNTC said:
Great but is my answer wrong?

Yes, your result is incorrect. :D

You want to add the two exponents to get 1/3 + 1/3 = 2/3.
 
MarkFL said:
Yes, your result is incorrect. :D

You want to add the two exponents to get 1/3 + 1/3 = 2/3.

I forgot that powers are added.
 
Well, what in the world did you do to get "1/6"?
 
Thank you everyone.
 

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