Calculating the speed of a JFET

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To calculate the speed of a JFET, it's essential to determine the capacitance of the junction between the P-doped gate and N-channel, which involves understanding the depletion width. The depletion width varies with the applied drain-source voltage, leading to a larger width near the drain. The abrupt junction approximation can be used to calculate this width at different points, but the capacitance calculation may require integration to account for the varying depletion width. Additionally, understanding how the N-channel width changes with applied voltage is crucial for accurate calculations. Clarifying these factors will aid in determining the RC time constant and ultimately the speed of the JFET.
Mr_Allod
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Homework Statement
How fast will a PN JFET operate in GHz if the gate impedance is ##50\omega##, and if the JFET
has a drain-source voltage ##V_{DS} = 2V##
Relevant Equations
Capacitance: ##C = \frac {\epsilon A}{h}##
##\epsilon_r = 11.7##
N-channel thickness ##T = 125nm##
N-channel width ##W = 75\mu m##
N-channel length ##L = 0.8\mu m##
##N_D = 4\times 10^{18} cm^{-3}##
##N_A = 2\times 10^{17} cm^{-3}##
Hello there, I believe here I need to find the capacitance of the junction between the P-doped gate and N-channel. Then I could find the RC time constant although I am not sure if there's something more I need to find the speed of the JFET?

What I'm unsure of is the depletion width h to use for the calculation. Since I am given a drain-source voltage ##V_{DS}## I think I am dealing with an uneven depletion layer, ie. the depletion layer is larger near the drain than it is near the source. I know how to calculate the width h at each point using the abrupt junction approximation but then I don't know what to actually use for the capacitance. Do I need to integrate in some way to account for the varying depletion width?

I'd appreciate some help with this.
 
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Is there a way to find how much the N-Channel width changes when the voltage is applied? The result after the change is what I would think is the ##h##.
 
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