If the radius of a merry-go-round is 11 meters, and it takes 15 seconds to go around once, what is the speed of an atom at the outer rim?
C = 2 [tex]\pi[/tex] r
v = m / s
The Attempt at a Solution
C = 3.14 * 22
(gives distance traveled, 1 trip)
Multiply by 2 (i.e. 2 trips as indicated by problem)
divide by the time, 15s
Answer was told to be wrong, I thought it rather simple, did I make a calculation error somewhere?